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An infinite number of charges each equal to 'q' are placed along the X-axis at x = 1, x = 2, x = 4, x = 8 ..... The potential at the point x = 0 due to this set of charges is

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$\frac{Q}{4 π \in_{o}}$

$\frac{2 Q}{4 π \in_{o}}$

$\frac{3 Q}{4 {πϵ}_{o}}$

$\frac{Q}{π \in_{o}}$

answer is B.

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Detailed Solution

$V = \frac{Q}{4 {πε}_{0}} [\frac{1}{1} + \frac{1}{2} + \frac{1}{4} + \frac{1}{8} + - - -]$

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