AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

An infinitely long current carrying thick cylindrical conductor, has a cylindrical cavity of radius $\frac{R}{2}$ . The axis of the cylindrical cavity is at a distance $\frac{R}{2}$ from the axis of the cylindrical conductor. A current with current density J flows along the length of the conductor. The magnetic field at a point ‘P’ at a distance 2R from the axis of the cylinder is (point ‘P’ is on the plane containing both the axes)

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

magnetic field at P is

\frac{μ_{0} JR}{6}

magnetic field on the axis of the cavity is non-zero

magnetic field at P is

\frac{μ_{0} JR}{12}

magnetic field on the axis of the conductor is non-zero

answer is B, C, D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Question Image

At (P) $B_{1}$ due to cylinder is $B_{1} = \frac{μ_{0} i_{1}}{2 π (2 R)} \otimes$

$B_{2} = \frac{μ_{0} i_{2}}{2 π (\frac{3 R}{2})} ⊙$

$i_{1} = J π R^{2} and i_{2} = J . \frac{π R^{2}}{4}$

$B_{P} = \frac{μ_{0} JR}{6}$

B on the axis of cavity due to cylinder is zero

B on the axis of cavity due to cylinder is $\frac{μ_{0} JR}{2}$ . Total field on the cavity is non – zero

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!