AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

An infinitely long thin non-conducting wire is parallel to the z-axis and carries a uniform line charge density $λ$ . It pierces a thin non-conducting spherical shell of radius R in such a way that the arc PQ subtends an angle 120° at the centre O of the spherical shell, as shown in the figure. The permittivity of free space is $ε_{0}$ . Which of the following statements is (are) true?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

The electric flux through the shell is $\sqrt{3} R λ / ε_{0}$

The z component of the electric field is zero at all the points on the surface of the shell

The electric flux through the shell is $\sqrt{2} R λ / ε_{0}$

The electric field is normal to the surface of the shell at all points

answer is A, B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Filed due to straight wire is perpendicular to the wire & radially outward. Hence $E_{z} = 0$ .

Length, $P Q = 2 R \sin 60 = \sqrt{3} R$

According to gauss’s law
Total flux= $\oint \vec{E} . \vec{d s} = \frac{q_{i n}}{\in_{0}} = \frac{λ \sqrt{3} R}{\in_{0}} (∵ L i n e a r c h a r g e d e n s i t y, λ = \frac{q}{l} \Rightarrow q = λ l = λ (P Q))$

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!