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Q.

An infinitely long wire bent into shape as shown in figure carries a steady current I. If the curved wire is along the curve  y2=4ax, then magnetic field at point  P(a,0), would be  μ0l4a(π+x2π)  


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answer is 2.

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Detailed Solution

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Apply Biot Savart’s law. 

B=B1+B2

B1 (Due to semi-infinite straight wire)  =μ0l4πa

B2  (Due to parabolic portion)  =μ0l8a

B=μ0l4a[1π+12]

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An infinitely long wire bent into shape as shown in figure carries a steady current I. If the curved wire is along the curve  y2=4ax, then magnetic field at point  P(a,0), would be  μ0l4a(π+x2π)