Q.

An infinitely long wire is bent in the form of a semicircle at the end as shown in the figure. It carries current I along abcdo. If radius of the semicircle be R, then the magnetic field at ‘O’ which is the centre of the circular part is
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a

μ04π2IR(π+1)

b

μ04π2IR(π1)

c

μ04πIR(π+1)

d

μ04πIR(π1)

answer is C.

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Detailed Solution

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B=μ0I4πR+μ0I2Rπ2π;B=μ0I4πR(1+π)

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