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Q.

An infinitesimal bar magnet of dipole moment M is pointing and moving with speed v in the x-direction. A closed circular conducting loop of radius α and negligible self-inductance lies in the y-z plane with its center at x = 0 and its axis coinciding with x-axis. Find the force opposing the motion of the magnet, if the resistance of the loop is R. Assume that the distance x of the magnet from the center of the loop is much greater than α.

An infinitesimal bar magnet of dipole moment M is pointing and moving with speed  v in the x-direction. A closed circular conducting loop of radius a ans negligible  self-inductance lies in the

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a

34μ02M2a4Rx8v

b

54μ02M2a4Rx8v

c

14μ02M2a4Rx8v

d

94μ02M2a4Rx8v

answer is B.

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Detailed Solution

The magnetic field of a bar magnet at its axial point, distance x from its center is given by, 

B=μ04π2Mx3

Magnetic flux linked with the loop 

ϕ=BA=μ04π2Mx3πa2

The induced emf in the loop due to motion of magnet

E=-dϕdt=μ04π6πMa2x4dxdt=μ04π6πMa2x4v

The induced current in the loop, 

I=ER=μ04π6πMa2Rx4v

The induced magnetic moment in the coil 

=I×A=μ04π6π2Ma4Rx4v

The magnetic force between two magnetic dipole is given by 

F=μ04π6M1M2x4

Hence opposing force 

F=94μ02M2a4Rx8v

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An infinitesimal bar magnet of dipole moment M is pointing and moving with speed v in the x-direction. A closed circular conducting loop of radius α and negligible self-inductance lies in the y-z plane with its center at x = 0 and its axis coinciding with x-axis. Find the force opposing the motion of the magnet, if the resistance of the loop is R. Assume that the distance x of the magnet from the center of the loop is much greater than α.