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An insulating pipe of cross-sectional are a A contains an electrolyte which has two types of ions: their charges being $- e$ and +2e. A potential difference applied between the ends of the pipe result in the drifting of the two types of ions, having drift speed = v (-ve ion) and v/4 (+ve ion).
Both ions have the same number per unit volume = n. The current flowing through the pipe is

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$\frac{1}{2} nevA$

$\frac{5}{2} nevA$

$\frac{3}{2} nevA$

$\frac{1}{4} nevA$

answer is D.

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Detailed Solution

$i = {nev}_{d} A; I = \frac{2 envA}{4} = - (- nevA) = \frac{3}{2} nevA$

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