An ion having a 4+ charge and a mass of 51.99 amu has two electrons with n=1, eight electrons with n=2, and ten electrons with n=3. Give the total number of protons present in the nucleus of the atom of metal.

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answer is 24.

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Detailed Solution

In $M^{4 +}$ ion total number of electrons =20
Electronic configuration = $\frac{1 s^{2}}{2} \frac{2 s^{2} 2 p^{6}}{8} \frac{3 s^{2} 3 p^{6} 3 d^{2}}{10}$
Number of electrons in metal = number of protons =4+20=24

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