An ionic compound contains 29.08% sodium, 40.56% sulphur and 30.36% oxygen by mass. What is the formula of the sulphur-containing anion in the compound?

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$S_{2} O_{3}^{2 -}$

$S_{2} O_{4}^{2 -}$

$S_{2} O_{5}^{2 -}$

$S_{2} O_{6}^{2 -}$

answer is A.

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Detailed Solution

$\begin{array}{l} Na : S : O \\ = \frac{29.08}{23} : \frac{40.56}{32} : \frac{30.36}{16} \\ = 1.26 : 1.26 : 1.90 \\ = 2 : 2 : 3 \\ {Na}_{2} S_{2} O_{3} \end{array}$

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