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Q.

An iron rod is placed coaxially inside a solenoid on which the number of turns per unit length is 600. The relative permeability of the rod is 1000. If a current of 0.5 A is passed through the solenoid, then the magnetization of the rod will be 

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a

2.997×104A/m

b

2.997×103A/m

c

2.997×102A/m

d

2.997×105A/m

answer is D.

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Detailed Solution

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as 1+χm=μr

χm=μr−1=1000−1=999

H=n  i=600×0.5=300

I=χmH=999×300=2.997×105A/m

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