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An iron rod is placed coaxially inside a solenoid on which the number of turns per unit length is 600. The relative permeability of the rod is 1000. If a current of 0.5 A is passed through the solenoid, then the magnetization of the rod will be

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$2.997 \times 10^{4} A / m$

$2.997 \times 10^{3} A / m$

$2.997 \times 10^{2} A / m$

$2.997 \times 10^{5} A / m$

answer is D.

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Detailed Solution

as $1 + χ_{m} = μ_{r}$

$χ_{m} = μ_{r} - 1 = 1000 - 1 = 999$

$H = n i = 600 \times 0.5 = 300$

$I = χ_{m} H = 999 \times 300 = 2.997 \times 10^{5} A / m$

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