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Q.

An iron rod is subjected to cycles of magnetization at the rate of 50 Hz. Given density of rod is 8×103kg/m3 and specific heat 0.11×103cal/kgC. If area enclosed by the B-H loop corresponds to energy of 102J then rise in temperature per minute is nearly is (Assume there is no radiation losses)

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a

78.5C

b

15C

c

8C

d

0.13C

answer is C.

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Detailed Solution

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Area enclosed by H-H loop equal to loss of energy per unit volume for one cycle. Let  E0 ' be the area.

 If ‘n’ is frequency, ‘nt’ cycles in time ‘t’.

 Total loss of energy for ‘V’ volume

E1=nt0V

msΔt=nt0.V

VdsΔt=nt0.V

Δt=nt0ds=8C

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