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An iron rod of $0.2 {cm}^{2}$ cross-sectional area is subjected to a magnetizing field of 1 $200 A m^{- 1}$ . The susceptibility of iron is 599. The magnetic flux produced is

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$0.904 x 10^{- 5} Wb$

0.904 Wb

$1.81 x 10^{- 5} Wb$

$5.43 x 10^{- 5} Wb$

answer is B.

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Detailed Solution

$μ = μ_{0} (1 + χ) or μ = 4 π x 10^{- 7} (1 + 599)$

or $μ = 7.536 x 10^{- 4} {TmA}^{- 1}$

$B = μH = 7.536 x 10^{- 4} x 1200 T$

$ϕ = BA = 7.536 x 10^{- 4} x 1200 x 0.2 x 10^{- 4} Wb$

$= 1.81 x 10^{- 5} Wb$

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