An iron sample having mass 8.4kg repeatedly taken over cycles of magnetisation and demagnetisation at the rate 50cps. It is found that 3.2×104 J of energy is dissipated as heat in 30min. Find energy dissipated perunit volume per cycle in the iron sample (density fo iron 7200 kg/m3)

Q=WV×ν×t=3.2×104×72008.4×50×1800=304.8J/m3 cycle

An iron sample having mass 8.4kg repeatedly taken over cycles of magnetisation and demagnetisation at the rate 50cps. It is found that 3.2×104 J of energy is dissipated as heat in 30min. Find energy dissipated perunit volume per cycle in the iron sample (density fo iron 7200 kg/m3)

Q=WV×ν×t=3.2×104×72008.4×50×1800=304.8J/m3 cycle

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An iron sample having mass 8.4kg repeatedly taken over cycles of magnetisation and demagnetisation at the rate 50cps. It is found that 3.2×10⁴ J of energy is dissipated as heat in 30min. Find energy dissipated perunit volume per cycle in the iron sample (density fo iron 7200 kg/m³)

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$Q = \frac{W}{V \times ν \times t} = \frac{3 .2 \times 10^{4} \times 7200}{8 .4 \times 50 \times 1800} = 304 .8 J / m^{3} cycle$

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An iron sample having mass 8.4kg repeatedly taken over cycles of magnetisation and demagnetisation at the rate 50cps. It is found that 3.2×104 J of energy is dissipated as heat in 30min. Find energy dissipated perunit volume per cycle in the iron sample (density fo iron 7200 kg/m3)

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An iron sample having mass 8.4kg repeatedly taken over cycles of magnetisation and demagnetisation at the rate 50cps. It is found that 3.2×10⁴ J of energy is dissipated as heat in 30min. Find energy dissipated perunit volume per cycle in the iron sample (density fo iron 7200 kg/m³)