An iron wire of length 4m and diameter 2mm loaded with weight of 8kg. If young’s modulus of iron is 2×1011N/m2 , find increase in length of wire is nearly ____

e=FLAY=8×10×4π×10−6×2×1011 e=10−5×160×0.32=32×16×10−6m e=5mm

An iron wire of length 4m and diameter 2mm loaded with weight of 8kg. If young’s modulus of iron is 2×1011N/m2 , find increase in length of wire is nearly ____

e=FLAY=8×10×4π×10−6×2×1011 e=10−5×160×0.32=32×16×10−6m e=5mm

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An iron wire of length 4m and diameter 2mm loaded with weight of 8kg. If young’s modulus of iron is $2 \times 10^{11} N / m^{2}$ , find increase in length of wire is nearly ____

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0.2mm

1mm

0.5mm

2mm

answer is D.

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Detailed Solution

$e = \frac{FL}{AY} = \frac{8 \times 10 \times 4}{π \times 10^{- 6} \times 2 \times 10^{11}} e = 10^{- 5} \times 160 \times 0.32 = 32 \times 16 \times 10^{- 6} m e = 5 mm$

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An iron wire of length 4m and diameter 2mm loaded with weight of 8kg. If young’s modulus of iron is 2×1011N/m2 , find increase in length of wire is nearly ____

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An iron wire of length 4m and diameter 2mm loaded with weight of 8kg. If young’s modulus of iron is $2 \times 10^{11} N / m^{2}$ , find increase in length of wire is nearly ____