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An isolated particle of mass rn is moving in a horizontal plane (x-y) along the X-axis. At a certain height above the ground, it suddenly explodes into two fragments of masses $\frac{m}{4} and \frac{3 m}{4}$ . An instant later, the smaller fragment is at Y = +15 cm. The larger fragment at this instant is at:

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Y = -5 cm

Y = +20 cm

Y = +5 cm

Y = -20 cm

answer is A.

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Detailed Solution

Initially coordinates of centre of mass is origin. Explosion is an internal force. That is after explosion the coordinate of centre of mass of the particles should be origin.

$\frac{m}{4} \times (15) = \frac{3}{4} m (Y) = 0 \Rightarrow Y = - 5 cm$

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