An LPG cylinder contains 15kg of butane gas at 270C and 10 atmospheric pressure. It was
leaking and its pressure fell down to 8 atmospheric pressure after one day. The gas leaked is ___kg

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answer is 3.

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Detailed Solution

$\begin{array}{l} ΔP = 2 atm \Rightarrow \frac{p_{1}}{w_{1}} = \frac{p_{2}}{w_{2}} \Rightarrow \frac{10}{15} = \frac{2}{x} \\ \Rightarrow x = 3 kg \end{array}$

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