An N - P - N transistor is connected in common - emitter configuration in which collector supply is 8V and the voltage drop across the load resistance of $800 Ω$ connected in the collector circuit is 0.8V. If current amplification factor is 25/26 (If the internal resistance of the transistor is $200 Ω$ ), the collector-emitter voltage, voltage gain and power gain are respectively.

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5.2V, 1.86, 3

6.2V, 186, 5.5

7.2V, 3.86, 3.698

8.2V, 4.91, 3.15

answer is C.

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Detailed Solution

The circuit arrangement is shown in figure

collector current $I_{C} = \frac{Voltage drop across R_{L}}{R_{L}}$
$= \frac{0 .8}{800} = 10^{- 3} amp$
Now V_CE = 8 - 0.8 = 7.2 volt
Current gain $β = \frac{I_{C}}{I_{B}} (or) \frac{25}{26} = \frac{10^{- 3}}{I_{B}}$
$∴ I_{B} = \frac{26}{25} \times 10^{- 3} = 1 .04 \times 10^{- 3} amp$
Voltage gain = $β \frac{R_{L}}{R_{C}}$
$= \frac{25}{26} \times \frac{800}{200} = \frac{100}{26} = 3 .846$
Power gain = $= β^{2} \frac{R_{L}}{R_{C}} = {(\frac{25}{26})}^{2} \times \frac{800}{200}$
$= {(\frac{25}{26})}^{2} \times 4 = 3 .698$