Q.

An object 5 cm high is placed at a distance of 10 cm from a convex lens of focal length 15 cm. Find the nature, position of the image.

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a

– 30 cm, virtual and erect

b

– 30 cm, real and erect

c

– 30 cm, real and inverted

d

– 30 cm, virtual and inverted

answer is A.

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Detailed Solution

Using Cartesian sign convention

Object distance = −10 cm

Focal length of a convex lens = 15 cm

Height of the object = h0 = 5 cm

Using lens formula 

1f=1v-1u 115=1v=1-10 115=1v+1101v=10-1515×10 v=-1505-30 cm

Negative sign indicates it is a virtual image

m=vu m=-30-10=3

Positive sign indicates the image is erect.

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