An object A B E D is placed in front of a concave mirror beyond centre of curvature C as shown in figure. State the shape of the image.

Object is placed beyond C. Hence, the image be real and it will lie between C and F. Further v and f all are negative, hence the mirror form becomes

$$\begin{gathered} -\frac{1}{v}-\frac{1}{u}=-\frac{1}{f} \\ \Rightarrow \frac{1}{v}=\frac{1}{f}-\frac{1}{u}=\frac{u-f}{uf} \\ \Rightarrow v=\frac{f}{1-\frac{f}{u}} \end{gathered}$$

Now since, $u_{AB}>u_{ED}$

$\Rightarrow v_{AB}<v_{ED}$

Hence, $\left|m_{AB}\right|<\left|m_{ED}\right|$                                      

Therefore, shape of the image will be as shown in figure.

Also note that $v_{AB}<u_{AB}and{v}_{ED}<u_{ED},\left|m_A\right|and\left|m_{ED}\right|<1$