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Q.

An object has charge of 1 C and gains 5.0 x 1018 electrons. The net charge on the object becomes.

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a

-0.80 C

b

+1.80 C

c

+0.80 C

d

+0.20 C

answer is D.

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Detailed Solution

Given:

  1. Initial charge of the object, Qinitial = +1 C.
  2. Number of electrons gained, N = 5.0 x 1018.

Step 1: Calculate the Total Charge Added by the Electrons

The charge of a single electron is approximately -1.6 x 10-19 C.

So, the total charge due to 5.0 x 1018 electrons is:

Qelectrons = N x charge of one electron

Qelectrons = (5.0 x 1018) x (-1.6 x 10-19) C

Qelectrons = -0.8 C

Step 2: Calculate the Net Charge on the Object

The initial charge on the object is +1 C, and it gains a charge of -0.8 C due to the electrons. Therefore, the net charge is:

Qnet = Qinitial + Qelectrons

Qnet = 1 C + (-0.8 C)

Qnet = 0.2 C

Answer:

The net charge on the object becomes +0.2 C.

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