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An object has mass $2 kg$ and density $8000 kg / m^{3}$ . What will be the volume of the object?

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3.5 \times 10^{- 4} m^{3}

2.5 \times 10^{- 4} m^{3}

5.35 \times 10^{- 4} m^{3}

4.3 \times 10^{- 4} m^{3}

answer is B.

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Detailed Solution

An object has mass

2 kg

and density

8000 kg / m^{3}

. The volume of the object is

2.5 \times 10^{- 4} m^{3}

.
Given that,

Density of liquid = 8000 kg / m^{3}

From the relation of volume, mass and density ,

volume = \frac{mass}{density}

On putting all the value in the above relation we get,

\Rightarrow volume = \frac{2}{8000}

\Rightarrow volume = 2.5 \times 10^{- 4} m^{3}

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