An object is approaching a fixed plane mirror with velocity 5ms−1 making an angle of 45∘ with the normal. The speed of image w.r.t. the mirror is

Speed of image w.r.t mirror:VI=522+522=5 ms−1

Speed of image w.r.t mirror:VI=522+522=5 ms−1

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An object is approaching a fixed plane mirror with velocity $5 {ms}^{- 1}$ making an angle of $45^{\circ}$ with the normal. The speed of image w.r.t. the mirror is

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$5 m s^{- 1}$

$\frac{5}{\sqrt{2}} {ms}^{- 1}$

$5 \sqrt{2} m s^{- 1}$

$10 {ms}^{- 1}$

answer is A.

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Speed of image w.r.t mirror:

$V_{I} = \sqrt{{(\frac{5}{\sqrt{2}})}^{2} + {(\frac{5}{\sqrt{2}})}^{2}} = 5 {ms}^{- 1}$

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