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Q.

An object is attached to the bottom of a light vertical spring and set vibrating. The maximum speed of the object is 15 cm / sec and the period is 628 m sec. The amplitude of the motion in centimeter is

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a

2

b

1.5

c

1.0

d

3

answer is C.

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Detailed Solution

Vmax=Aω15=A×2π628×103=A×2×3.146.28×101A=15×101cmA=1.5cm

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