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An object is dropped from a certain height. After $2$ seconds, the velocity of the object will be (take $g = 9.8 m / s^{2}$ )

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19.6 m / s

9.8 m / s

4.9 m / s

0 m / s

answer is A.

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Detailed Solution

The velocity of the object will be

19.6

m/s.
The initial velocity of the object,

u = 0 m / s

Acceleration due to gravity,

g = 9.8 m / s^{2}

Velocity after two seconds can be found using the equations of motion for uniformly accelerated motion.

v = u + at

v = 0 + 9.8 \times 2

v = 19.6 m / s

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