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An object is moving towards a concave mirror of focal length 24 $c m$ . When it is at a distance of 60 $c m$ from the mirror, its speed is 9 $c m / s$ . The speed of its image at that instant, is

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4 $c m / s$ towards the mirror

6 $c m / s$ towards the mirror

4 $c m / s$ away from the mirror

6 $c m / s$ away from the mirror

answer is C.

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Detailed Solution

$\frac{1}{v} + \frac{1}{- 60} = \frac{1}{- 24} ∴ v = - 40 c m m = - \frac{v}{u} = - \frac{- 40}{(- 60)} = - \frac{2}{3}$

Image speed is $m^{2}$ times the object speed and opposite to the direction of object velocity.

Image speed = ${(\frac{2}{3})}^{2} \times 9 = 4 c m / s$

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