An object is placed 12 cm to the left of a converging lens of focal length 8 cm. Another converging lens of 6 cm focal length is placed at a distance of 30 cm to the right of the first lens. The second lens will produce

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A real enlarged image

No image

A virtual enlarged image

A real smaller image

answer is C.

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Detailed Solution

$For lens (1) \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \Rightarrow \frac{1}{(+ 8)} = \frac{1}{v} - \frac{1}{(- 12)} \Rightarrow v = 24 cm,$ i.e., Image A,B, is obtained 6 cm before the lens 2 or at the focus of lens 2. Hence final image formed by lens 2 will be real enlarged and it is obtained at $\infty$ .

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