An object is placed 30 cm to the left of a diverging lens whose focal length is of magnitude 20 cm. Which one of the following correctly states the nature and position of the virtual image formed?

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

Nature of image: inverted, enlarged; distance form lens: 60 cm to the left

Nature of image: inverted, enlarged; distance form lens: 60 cm to the right

Nature of image: erect, diminished; distance form lens: 12 cm to the right

Nature of image: erect, diminished; distance form lens: 12 cm to the left

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

When an object is placed between 2 f and f (focal length) of the diverging lens, the image is virtual, erect and diminished as shown in the graph. To compute the distance of the image from the lens, we apply

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u} \Rightarrow \frac{1}{- 20} = \frac{1}{v} - \frac{1}{30} \Rightarrow v = - \frac{(20) (30)}{20 + 30}$ = - 12 cm (to the left of the diverging lens.)