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An object is placed at a distance of $12 cm$ in front of a concave mirror. It forms a real image four times larger than the object. Calculate the distance of the image from the mirror.

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v = - 28 cm

v = - 48 cm

v = - 38 cm

v = - 58 cm

answer is B.

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Detailed Solution

Distance of the image from the mirror . v = - 48 cm

Here,

u = distance of an object from the mirror

v = distance of the image from the mirror

u = - 12 cm

m = - 4

(∵ from real image the value if

m

is negative)
According to the magnification formula,

m = - \frac{v}{u}

\Rightarrow 4 \times (- 12) = v

v = - 48 cm

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