AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

An object is placed at a distance of $30 cm$ and $3 cm$ high, perpendicular to the principal axis of a concave lens of a focal length of $15 cm$ . The image is formed at a distance of $10 cm$ in front of the lens. What would be the nature and size of the image formed?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

Virtual and erect,

3 cm

Virtual and erect ,

1 cm

Virtual and erect ,

2 cm

Virtual and erect ,

1.5 cm

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

The size of the image formed is

1 cm

, and nature is virtual and erect.
Given,
Image distance,

v = - 10 cm

, [Negative as the image is formed in front of the lens]
Object distance,

u = - 30 cm

and
Object height,

h = 3 cm

.
It is known that the magnification produced is the ratio of the image distance

(v)

to the object distance

(u)

. It can also be defined as the ratio of the image height

(h')

to the object height

(h)

. Mathematically,

m = \frac{v}{u} = \frac{h'}{h}

On substituting the given values, we get the image height as

(h')

\Rightarrow \frac{v}{u} = \frac{h'}{h}

\Rightarrow h' = \frac{hv}{u}

\Rightarrow h' = \frac{3 \times - 10}{- 30}

\Rightarrow h' = + 1 cm

A positive sign indicates that the image will be erect. A concave lens always forms a virtual image. It can be said that the lens formed a virtual, erect and diminished image.

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

best study material, now at your finger tips!

live classes
progress tracking
24x7 mentored guidance
study plan analysis

download the app

An object is placed at a distance of 30 cm and 3 cm high, perpendicular to the principal axis of a concave lens of a focal length of 15 cm. The image is formed at a distance of 10 cm in front of the lens. What would be the nature and size of the image formed?

Best Courses for You

Detailed Solution

courses

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

download the app

Download the App

An object is placed at a distance of $30 cm$ and $3 cm$ high, perpendicular to the principal axis of a concave lens of a focal length of $15 cm$ . The image is formed at a distance of $10 cm$ in front of the lens. What would be the nature and size of the image formed?