An object is placed in a medium of refractive index 3. An electromagnetic wave of intensity $6 \times 10^{8} W / m^{2}$ falls normally on the object and it is absorbed completely. The radiation pressure on the object would be (speed of light in free space $= 3 \times 10^{8} m / s$ )

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$2 {Nm}^{- 2}$

$36 {Nm}^{- 2}$

$6 {Nm}^{- 2}$

$18 {Nm}^{- 2}$

answer is C.

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Detailed Solution

Radiation pressure
$p = \frac{I}{C_{m}} = \frac{I \times μ}{C} = \frac{6 \times 10^{8} \times 3}{3 \times 10^{8}} = 6 N m^{- 2}$

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