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An object is placed perpendicular to the principal axis of a convex lens of focal length $8 cm$ . The distance of the object from the lens is $12 cm$ . Nature of the image will be ____.

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Detailed Solution

An object is placed perpendicular to the principal axis of a convex lens of focal length

8 cm

. The distance of the object from the lens is

12 cm

. Nature of the image will be real and inverted.
Object distance,

u = - 12 cm

,
Focal length

f = + 8 cm

“Using lens formula,

\frac{1}{f} = \frac{1}{v} - \frac{1}{u}

Where

v

is the distance of the image from the lens,

u

is the distance of the object from the lens, and

f

is the focal length of the lens.”

\frac{1}{8} = \frac{1}{v} - \frac{1}{(- 12)}

v = + 24 cm .

Now, Magnification,

m = \frac{v}{u}

\Rightarrow m = \frac{v}{u}

\Rightarrow m = \frac{24}{- 12}

m = - 2

The negative sign shows that the image is real and inverted.

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