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An object is thrown upwards with a velocity of $19.6 m / s$ from the ground. How much time will it take to return to its original position ?

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0

5 s

4 s

2 s

answer is C.

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Detailed Solution

It takes

4 s

to return to its original position.
The object will return back to the same point with

19.6 m / s

but downward, therefore its displacement will be zero. The following equation can be used to calculate the amount of time needed to reach the highest point.

v = u + gt

…

(1)

Initial velocity

u = 19.6 m / s

and gravitational acceleration

g = 9.8 m / s^{2}

Put these values in equation (1).

\Rightarrow 0 = 19.6 + (- 9.8 t)

(here negative sign indicates the direction of acceleration)

\Rightarrow t = 19.8 / 9.8

\Rightarrow t = 2 s

So, the object takes the same amount of time to come back to its original position.
Total time

= 2 \times 2

Total time

= 4 s

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