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An object is thrown vertically upward with a speed of 30 m/s. The velocity of the object half-a-second before it reaches the maximum height is

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19.6m/s

25.1m/s

4.9m/s

9.8m/s

answer is A.

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Detailed Solution

Velocity half second before maximum height = Velocity half second after maximum height (Return journey)

For downward journey :

Initial velocity u = 0 m/s

We have g = 9.8 m/s²

Time t = 1/2 s

Thus velocity after half second v = u + gt

v = 0 + 9.8 × 1/2 = 4.9m/s

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