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Q.

An object is thrown vertically upwards and rises to a height of x m. If the velocity with which the object was thrown upwards is 28 ms⁻¹, find x

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a

40 m

b

16 m

c

20 m

d

17 m

answer is A.

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Detailed Solution

Distance travelled, s = x m
Initial velocity u = 28 ms⁻¹
Final velocity, v = 0 m s⁻¹
a = g = - 9.8 ms⁻² (upward motion)

v² - u² = 2as 
- 28² = 2(- 9.8)s 
s = 784 ÷ 19.6
s = 40
 

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