An object moves along x-axis such that its velocity varies with time as $v = (50 - 10 t) \frac{m}{s}$ , where t is time in seconds. Average speed of the particle in the time interval t= 0 to t= 6s is equal to

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$\frac{75}{2} \frac{m}{s}$

$\frac{65}{3} \frac{m}{s}$

$20 \frac{m}{s}$

$40 \frac{m}{s}$

answer is B.

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Detailed Solution

$v = 50 - 10 t \frac{m}{s}$

$S = A_{1} + A_{2} = \frac{1}{2} \times 5 \times 50 + \frac{1}{2} \times 1 \times 10 = 130 m < V > = \frac{S_{t o f}}{t_{t o f}} = \frac{130}{6} = \frac{65}{3} \frac{m}{s}$

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