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Q.

An object moves at a constant speed along a circular path in a horizontal plane with center at the origin. When the object is at x=+2m, its velocity is −4j^ m/s. The object’s velocity (v) and acceleration (a) at x=−2m will be

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a

v=4j ^m/s, a=8i ^m/s2

b

v=−4j ^m/s, a=8i ^m/s2

c

v=−4i ^m/s, a=−8j^ m/s2

d

v=4i ^m/s, a=8j^ m/s2

answer is A.

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Detailed Solution

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at x=+2m, the velocity is tangential and directed along +y-axis direction.

ar=v2R=422=8, directed towards the centre(+x-direction).

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