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Q.

An object O is kept on the principal axis of a concave mirror at a distance 200 cm from pole of the mirror. By some mechanism radius of curvature of mirror is changing with time as R=200tcm  , here t is in second. Column-I shows the time instant, Column-II represents velocity of image at that time and Column-III represents acceleration of image at the time.

Question Image
        Time      Velocity of image     Acceleration of image
A) 1 secP)  40049cm/s1)  645cm/s2 
B) 2 secQ) 16 cm/s2)  1600343cm/s2
C) 3 secR)  4009cm/s3)  160027cm/s2
D) 4 secS) 400 cm/s4) 1600 cm/s2

Which of the following is correctly matched? 

 

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a

(A)(S)(4)

b

(A)(Q)(4)

c

(A)(S)(1)

d

(A)(Q)(1)

answer is A.

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Detailed Solution

 2f=200t1f=t100 1f=1v+1ut100=1v1200
 
Image distance  v=20012t
Velocity of image =  dvdt=200×2(12t)2
         = 400(12t)2 
Acceleration of image =  d2vdt2
   =  2×400×2(12t)3 = 1600(12t)3 . 
 

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