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Q.

An object 'O' is placed at a distance of 100 cm in front of a concave mirror of radius of curvature 200 cm as shown in the figure. The object starts moving towards the mirror at a speed 2 cm/s. The position of the image from the mirror after 10s will be at ......... cm.

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answer is 400.

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Detailed Solution

After 10 sec.

u = -80 cm

f = -100cm

$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$

v = 400cm

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