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Q.

An object O is placed at a distance of 100 cm in front of a concave mirror of radius of curvature 200cm as shown in the figure. The object starts moving towards the mirror at a speed 2cm/s. The position of the image from the mirror after 10 s will be at ____ cm.

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a

100

b

400

c

200

d

300

answer is A.

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Detailed Solution

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distance of the object after 10 sec 100-2 $\times 10$ =80cm=U

$Applying mirror equation - \frac{1}{80} + \frac{1}{v} = \frac{- 1}{100}$

v=400 cm

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