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An object O is placed infront of two convex mirrors having $R_{1} = 20 c m$ and $R_{2} = 30 c m$ at a distance 15 cm as shown in figure then we observe more diminished image in

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we cannot decide

M_{2}

same size in both

M_{1} a n d M_{2}

M_{1}

answer is A.

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Detailed Solution

given

$R_{1} = 20 c m, u = 15 c m, f = 10 c m t h e n m = \frac{f}{p}$

$R_{2} = 30 c m, u = 15 c m, f = 15 c m$

P is distance between object and focus

$m_{1} = \frac{10}{25}, m_{2} = \frac{15}{30}$

$\Rightarrow m_{1} = \frac{2}{5}, m_{2} = \frac{1}{2}$

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