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Q.

An object of height Question Image is placed at a distance of Question Image from the optical centre 'O' of a convex lens of focal length Question Image. Add diagramMark optical centre ' Question Image ' and principal focus 'F' on the diagram. The approximate ratio of size of the image to the size of the object is ____ and the size of image is ____cm.


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Detailed Solution

Concept- The approximate ratio of size of the image to the size of the object is 2: 1. To get the value of image distance, use the lens formula. Draw the entire device as a ray diagram after that. Lastly, determine the picture's magnification and size, which are correlated with the distance between the image and the object.
Formula Used:
Lens equation is Question ImageAnd the magnification, Question ImageGiven that an object of height Question Image is placed at a distance of Question Image from the optical centre 'O' of a convex
lens of focal length Question Image.
Question Image By sign convention since image is kept at the left of the lens
Question ImageQuestion ImageUsing lens equation we get,
Question ImageQuestion ImageWe put the values of the known quantities
Question ImageQuestion ImageQuestion ImageThus the image is formed at the right side of the lens at a distance of Question Image from the lens.
Now we represent the above problem in a ray diagram
Question ImageHere the optical centre ' Question Image ' and principal focus ' Question Image ' are marked on the diagram
Now we know that,
Question ImageQuestion ImagePutting the values we get,
Question ImageQuestion ImageThe negative sign here shows that the image is inverted and hence real.
Thus the approximate ratio of size of the image to the size of the object is 2: 1
Again
Question ImageQuestion ImageSo, the size of image isQuestion Image.
Hence, the correct answer is 2:1 and 8 cm.
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