An object of length 10 cm is placed at right angles to the principal axis of a mirror of radius of curvature 60 cm such that its image is virtual, erect and has a length 6 cm. What kind of mirror it is and also determine the position of the object ?

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Concave, 20 cm from the mirror

Convex, 20 cm from the mirror

Convex, 10 cm from the mirror

Concave, 10 cm from the mirror

answer is B.

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Detailed Solution

Linear magnification $m = \frac{6}{10} = 0 .6 < 1 i.e$ the image is diminished.
This can be formed by convex mirror only. [virtual image formed by concave mirror is always magnified].

Now $f = + \frac{R}{2} = + 30 cm; m = \frac{f}{f - u}$

$\Rightarrow \frac{6}{10} = \frac{30}{30 - u}, 50 = 30 - u; u = - 20 cm$

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