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Q.

An object of mass 0.5 kg is executing simple harmonic motion. Its amplitudes is 5 cm and time period (T) is 0.2 s. What will be the potential energy of the object at an instant t=T4s starting from mean position. Assume that the initial phase of the oscillation is zero.

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a

6.2×10-3 J

b

0.62 J

c

6.2×103 J

d

1.2×103 J

answer is A.

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Detailed Solution

P.E=12mω2x2

12m2πT2×A2sin22πTt

Putting value of m, A and T, we get P.E=0.62 J

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