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Q.

An object of mass 10 kg is released from rest in a liquid. If the object moves a distance of 2m while sinking in time duration of 1s,  then the mass of the liquid displaced by the submerged object is (Acceleration due to gravity  =10 m s−2)

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a

4 kg 

b

3 kg 

c

5 kg 

d

6 kg 

answer is B.

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Detailed Solution

s=12at2    ⇒2=12a12      ∴a=4 m/s2

mg−Fb=ma    ⇒Fb=mg−ma

=10×10−10×4=60=6 kg weight

∴ mass of liquid displaced 6 kg 

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