An object of mass 10kg is whirled round a horizontal circle of radius 4m by a revolving string inclined 30∘ to vertical. If the uniform speed of the object is 5m/sec, the tension in the string (approximately) is ___ N

Tsin⁡θ=mV2r⇒T=10×2512×4=125N

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An object of mass 10kg is whirled round a horizontal circle of radius 4m by a revolving string inclined $30^{\circ}$ to vertical. If the uniform speed of the object is 5m/sec, the tension in the string (approximately) is ___ N

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answer is 125.

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$Tsin θ = \frac{{mV}^{2}}{r}$

$\Rightarrow T = \frac{10 \times 25}{\frac{1}{2} \times 4} = 125 N$

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