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An object of mass 10kg. Moves at a constant speed of $10 m s^{- 1}$ . A constant force, that acts for 4 sec on the object, gives it a speed of $2 m s^{- 1}$ in opposite direction. The force acting on the object is

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$3 N$

$- 30 N$

$- 3 N$

$30 N$

answer is B.

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Detailed Solution

Here $u = 10 m s^{- 1}, v = - 2 m s^{- 1}$

$t = 4 s, a = ?$

Using $a = \frac{v - u}{t} = \frac{- 2 - 10}{4} = - 3 m / s^{2}$

$∴$ Force, $F = m a = 10 \times (- 3) = - 30 N$

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