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Q.

An object of mass 10kg. Moves at a constant speed of 10ms−1 . A constant force, that acts for 4 sec on the object, gives it a speed of 2ms−1  in opposite direction. The force acting on the object is

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a

−3N

b

−30N

c

3N

d

30N

answer is B.

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Detailed Solution

Here u=10ms−1,v=−2ms−1

t=4s,  a=?

Using a=v−ut=−2−104=−3m/s2

∴  Force, F=ma=10×(−3)=−30N

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