An object of mass 2 kg and density 8000 kg/m3 of volume 2.5× 10-4 m3 will exert force of buoyancy [[1]] N in a liquid of density 8000 kg/m3.

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An object of mass $2 kg$ and density $8000 kg / m^{3}$ of volume $2.5 \times 10^{- 4} m^{3}$ will exert force of buoyancy [[1]] $N$ in a liquid of density $8000 kg / m^{3}$ .

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Detailed Solution

An object of mass

2 kg

and density

8000 kg / m^{3}

of volume

2.5 \times 10^{- 4} m^{3}

will exert force of buoyancy

2 N

in a liquid of density

8000 kg / m^{3}

.
Given that,

Density of liquid = 8000 kg / m^{3}

Volume of the object = 2.5 \times 10^{- 4} m^{3}

We know that buoyant force is equal to the product of volume of liquid displaced, density and gravitational acceleration.

Buoyant force = volume of liquid displace \times density of liquid \times g

On putting all the values in this relation we get,

\Rightarrow Buoyant force =

2.5 \times 10^{- 4} m^{3} \times 8000 kg / m^{3} \times 10 {m / s}^{2}

\Rightarrow Buoyant force = 2 N

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