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An object of mass $2 kg$ is thrown vertically upwards with an initial velocity $20 m / s$ . The potential energy at the end of $2 s$ is [[1]] $J$ . The gravitational acceleration is $10 m / s^{2}$

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Detailed Solution

An object of mass

2 kg

is thrown vertically upwards with an initial velocity

20 m / s

. The potential energy at the end of

2 s

400

J

.
Mathematically, Potential energy

(P . E .)

can be expressed as

P . E . = mgh

Where

m

is the mass of the object,

g

is the acceleration due to gravity and

h

is the height of the object.
It has been given that,
the mass is

(m) = 50 kg

and
the gravitational acceleration is

(g) = - 10 m / s^{2}

. (

-

sign, as acceleration is acting downward)
Time taken

(t) = 2 s

Initial velocity

(u) = 20 m / s

Using the second equation of motion, the height after

2 seconds

h = ut + \frac{1}{2} g t^{2}

\Rightarrow h = (20 \times 2) + \frac{1}{2} \times (- 10) \times 2^{2}

\Rightarrow h = 20 m

Therefore, potential energy of the object after

2

s will be

P . E . = 2 \times 10 \times 20 J

P . E . = 400 J

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