An object of mass 500 g, initially at rest, is acted upon by a variable force whose X-component varies with X in the manner shown. The velocities of the object at the points X = 8 m and X = 12 m, would have the respective values of (nearly)

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

18 m/s and 20.6 m/s

18 m/s and 24.4 m/s

23 m/s and 24.4 m/s

23 m/s and 20.6 m/s

answer is D.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

From work-energy theorem

$ΔK = work = area under F - x graph ,$

$From x = 0 to x = 8 m, \frac{1}{2} {mv}^{2} = 100 + 30$

$\Rightarrow v^{2} = 520 \Rightarrow v = \sqrt{520} ≃ 23 m / s$

$From x = 0 to x = 12 m, \frac{1}{2} {mv}^{2} = 100 + 30 - 47.5 + 20$

$\Rightarrow v = \sqrt{410} \Rightarrow v ≃ 20.6 m / s Hence appropriate option is 23 m / s and 20.6 m / s$

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test